(4x+1)(x^2-1)=

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Solution for (4x+1)(x^2-1)= equation: 


Simplifying
(4x + 1)(x2 + -1) = 0

Reorder the terms:
(1 + 4x)(x2 + -1) = 0

Reorder the terms:
(1 + 4x)(-1 + x2) = 0

Multiply (1 + 4x) * (-1 + x2)
(1(-1 + x2) + 4x * (-1 + x2)) = 0
((-1 * 1 + x2 * 1) + 4x * (-1 + x2)) = 0
((-1 + 1x2) + 4x * (-1 + x2)) = 0
(-1 + 1x2 + (-1 * 4x + x2 * 4x)) = 0
(-1 + 1x2 + (-4x + 4x3)) = 0

Reorder the terms:
(-1 + -4x + 1x2 + 4x3) = 0
(-1 + -4x + 1x2 + 4x3) = 0

Solving
-1 + -4x + 1x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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